Optimal. Leaf size=761 \[ -\frac{\tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+b x+c x^2}}\right ) \left (4 c f (b e-a f)+b^2 f^2-8 c^2 \left (e^2-d f\right )\right )}{8 c^{3/2} f^3}-\frac{\left (f \left (a f \left (-e \sqrt{e^2-4 d f}-2 d f+e^2\right )-b \left (-e^2 \sqrt{e^2-4 d f}+d f \sqrt{e^2-4 d f}-3 d e f+e^3\right )\right )+c \left (2 d^2 f^2-4 d e^2 f+2 d e f \sqrt{e^2-4 d f}-e^3 \sqrt{e^2-4 d f}+e^4\right )\right ) \tanh ^{-1}\left (\frac{4 a f+2 x \left (b f-c \left (e-\sqrt{e^2-4 d f}\right )\right )-b \left (e-\sqrt{e^2-4 d f}\right )}{2 \sqrt{2} \sqrt{a+b x+c x^2} \sqrt{2 a f^2-\sqrt{e^2-4 d f} (c e-b f)-b e f-2 c d f+c e^2}}\right )}{\sqrt{2} f^3 \sqrt{e^2-4 d f} \sqrt{f \left (2 a f-b \left (e-\sqrt{e^2-4 d f}\right )\right )+c \left (-e \sqrt{e^2-4 d f}-2 d f+e^2\right )}}+\frac{\left (f \left (a f \left (e \sqrt{e^2-4 d f}-2 d f+e^2\right )-b \left (e^2 \sqrt{e^2-4 d f}-d f \sqrt{e^2-4 d f}-3 d e f+e^3\right )\right )+c \left (2 d^2 f^2-4 d e^2 f-2 d e f \sqrt{e^2-4 d f}+e^3 \sqrt{e^2-4 d f}+e^4\right )\right ) \tanh ^{-1}\left (\frac{4 a f+2 x \left (b f-c \left (\sqrt{e^2-4 d f}+e\right )\right )-b \left (\sqrt{e^2-4 d f}+e\right )}{2 \sqrt{2} \sqrt{a+b x+c x^2} \sqrt{2 a f^2+\sqrt{e^2-4 d f} (c e-b f)-b e f-2 c d f+c e^2}}\right )}{\sqrt{2} f^3 \sqrt{e^2-4 d f} \sqrt{f \left (2 a f-b \left (\sqrt{e^2-4 d f}+e\right )\right )+c \left (e \sqrt{e^2-4 d f}-2 d f+e^2\right )}}-\frac{\sqrt{a+b x+c x^2} (-b f+4 c e-2 c f x)}{4 c f^2} \]
[Out]
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Rubi [A] time = 8.37725, antiderivative size = 761, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 6, integrand size = 30, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.2 \[ -\frac{\tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+b x+c x^2}}\right ) \left (4 c f (b e-a f)+b^2 f^2-8 c^2 \left (e^2-d f\right )\right )}{8 c^{3/2} f^3}-\frac{\left (f \left (a f \left (-e \sqrt{e^2-4 d f}-2 d f+e^2\right )-b \left (-e^2 \sqrt{e^2-4 d f}+d f \sqrt{e^2-4 d f}-3 d e f+e^3\right )\right )+c \left (2 d^2 f^2-4 d e^2 f+2 d e f \sqrt{e^2-4 d f}-e^3 \sqrt{e^2-4 d f}+e^4\right )\right ) \tanh ^{-1}\left (\frac{4 a f+2 x \left (b f-c \left (e-\sqrt{e^2-4 d f}\right )\right )-b \left (e-\sqrt{e^2-4 d f}\right )}{2 \sqrt{2} \sqrt{a+b x+c x^2} \sqrt{2 a f^2-\sqrt{e^2-4 d f} (c e-b f)-b e f-2 c d f+c e^2}}\right )}{\sqrt{2} f^3 \sqrt{e^2-4 d f} \sqrt{f \left (2 a f-b \left (e-\sqrt{e^2-4 d f}\right )\right )+c \left (-e \sqrt{e^2-4 d f}-2 d f+e^2\right )}}+\frac{\left (f \left (a f \left (e \sqrt{e^2-4 d f}-2 d f+e^2\right )-b \left (e^2 \sqrt{e^2-4 d f}-d f \sqrt{e^2-4 d f}-3 d e f+e^3\right )\right )+c \left (2 d^2 f^2-4 d e^2 f-2 d e f \sqrt{e^2-4 d f}+e^3 \sqrt{e^2-4 d f}+e^4\right )\right ) \tanh ^{-1}\left (\frac{4 a f+2 x \left (b f-c \left (\sqrt{e^2-4 d f}+e\right )\right )-b \left (\sqrt{e^2-4 d f}+e\right )}{2 \sqrt{2} \sqrt{a+b x+c x^2} \sqrt{2 a f^2+\sqrt{e^2-4 d f} (c e-b f)-b e f-2 c d f+c e^2}}\right )}{\sqrt{2} f^3 \sqrt{e^2-4 d f} \sqrt{f \left (2 a f-b \left (\sqrt{e^2-4 d f}+e\right )\right )+c \left (e \sqrt{e^2-4 d f}-2 d f+e^2\right )}}-\frac{\sqrt{a+b x+c x^2} (-b f+4 c e-2 c f x)}{4 c f^2} \]
Warning: Unable to verify antiderivative.
[In] Int[(x^2*Sqrt[a + b*x + c*x^2])/(d + e*x + f*x^2),x]
[Out]
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Rubi in Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(x**2*(c*x**2+b*x+a)**(1/2)/(f*x**2+e*x+d),x)
[Out]
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Mathematica [B] time = 6.3054, size = 1546, normalized size = 2.03 \[ \sqrt{a+x (b+c x)} \left (\frac{x}{2 f}-\frac{4 c e-b f}{4 c f^2}\right )-\frac{\left (-c e^4+b f e^3+c \sqrt{e^2-4 d f} e^3-a f^2 e^2+4 c d f e^2-b f \sqrt{e^2-4 d f} e^2-3 b d f^2 e+a f^2 \sqrt{e^2-4 d f} e-2 c d f \sqrt{e^2-4 d f} e+2 a d f^3-2 c d^2 f^2+b d f^2 \sqrt{e^2-4 d f}\right ) \sqrt{a+x (b+c x)} \log \left (-e-2 f x+\sqrt{e^2-4 d f}\right )}{\sqrt{2} f^3 \sqrt{e^2-4 d f} \sqrt{c e^2-b f e-c \sqrt{e^2-4 d f} e+2 a f^2-2 c d f+b f \sqrt{e^2-4 d f}} \sqrt{c x^2+b x+a}}-\frac{\left (c e^4-b f e^3+c \sqrt{e^2-4 d f} e^3+a f^2 e^2-4 c d f e^2-b f \sqrt{e^2-4 d f} e^2+3 b d f^2 e+a f^2 \sqrt{e^2-4 d f} e-2 c d f \sqrt{e^2-4 d f} e-2 a d f^3+2 c d^2 f^2+b d f^2 \sqrt{e^2-4 d f}\right ) \sqrt{a+x (b+c x)} \log \left (e+2 f x+\sqrt{e^2-4 d f}\right )}{\sqrt{2} f^3 \sqrt{e^2-4 d f} \sqrt{c e^2-b f e+c \sqrt{e^2-4 d f} e+2 a f^2-2 c d f-b f \sqrt{e^2-4 d f}} \sqrt{c x^2+b x+a}}+\frac{\left (8 e^2 c^2-8 d f c^2+4 a f^2 c-4 b e f c-b^2 f^2\right ) \sqrt{a+x (b+c x)} \log \left (b+2 c x+2 \sqrt{c} \sqrt{c x^2+b x+a}\right )}{8 c^{3/2} f^3 \sqrt{c x^2+b x+a}}+\frac{\left (c e^4-b f e^3+c \sqrt{e^2-4 d f} e^3+a f^2 e^2-4 c d f e^2-b f \sqrt{e^2-4 d f} e^2+3 b d f^2 e+a f^2 \sqrt{e^2-4 d f} e-2 c d f \sqrt{e^2-4 d f} e-2 a d f^3+2 c d^2 f^2+b d f^2 \sqrt{e^2-4 d f}\right ) \sqrt{a+x (b+c x)} \log \left (-b e^2-2 c x e^2-2 c \sqrt{e^2-4 d f} x e-b \sqrt{e^2-4 d f} e+4 b d f+8 c d f x+2 b f \sqrt{e^2-4 d f} x+4 a f \sqrt{e^2-4 d f}+2 \sqrt{2} \sqrt{e^2-4 d f} \sqrt{c e^2-b f e+c \sqrt{e^2-4 d f} e+2 a f^2-2 c d f-b f \sqrt{e^2-4 d f}} \sqrt{c x^2+b x+a}\right )}{\sqrt{2} f^3 \sqrt{e^2-4 d f} \sqrt{c e^2-b f e+c \sqrt{e^2-4 d f} e+2 a f^2-2 c d f-b f \sqrt{e^2-4 d f}} \sqrt{c x^2+b x+a}}+\frac{\left (-c e^4+b f e^3+c \sqrt{e^2-4 d f} e^3-a f^2 e^2+4 c d f e^2-b f \sqrt{e^2-4 d f} e^2-3 b d f^2 e+a f^2 \sqrt{e^2-4 d f} e-2 c d f \sqrt{e^2-4 d f} e+2 a d f^3-2 c d^2 f^2+b d f^2 \sqrt{e^2-4 d f}\right ) \sqrt{a+x (b+c x)} \log \left (b e^2+2 c x e^2-2 c \sqrt{e^2-4 d f} x e-b \sqrt{e^2-4 d f} e-4 b d f-8 c d f x+2 b f \sqrt{e^2-4 d f} x+4 a f \sqrt{e^2-4 d f}+2 \sqrt{2} \sqrt{e^2-4 d f} \sqrt{c e^2-b f e-c \sqrt{e^2-4 d f} e+2 a f^2-2 c d f+b f \sqrt{e^2-4 d f}} \sqrt{c x^2+b x+a}\right )}{\sqrt{2} f^3 \sqrt{e^2-4 d f} \sqrt{c e^2-b f e-c \sqrt{e^2-4 d f} e+2 a f^2-2 c d f+b f \sqrt{e^2-4 d f}} \sqrt{c x^2+b x+a}} \]
Antiderivative was successfully verified.
[In] Integrate[(x^2*Sqrt[a + b*x + c*x^2])/(d + e*x + f*x^2),x]
[Out]
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Maple [B] time = 0.028, size = 14815, normalized size = 19.5 \[ \text{output too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(x^2*(c*x^2+b*x+a)^(1/2)/(f*x^2+e*x+d),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(sqrt(c*x^2 + b*x + a)*x^2/(f*x^2 + e*x + d),x, algorithm="maxima")
[Out]
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(sqrt(c*x^2 + b*x + a)*x^2/(f*x^2 + e*x + d),x, algorithm="fricas")
[Out]
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Sympy [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{x^{2} \sqrt{a + b x + c x^{2}}}{d + e x + f x^{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x**2*(c*x**2+b*x+a)**(1/2)/(f*x**2+e*x+d),x)
[Out]
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GIAC/XCAS [F(-2)] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: TypeError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(sqrt(c*x^2 + b*x + a)*x^2/(f*x^2 + e*x + d),x, algorithm="giac")
[Out]